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std::set_symmetric_difference

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< cpp‎ | algorithm

 
 
Biblioteca algoritmo
Funções
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Functions
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Não modificar operações de seqüência
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Non-modifying sequence operations
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Modificando operações de seqüência
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Modifying sequence operations
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Particionamento operações
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Partitioning operations
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Operações de classificação (em intervalos ordenados)
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Sorting operations (on sorted ranges)
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Binários operações de busca (em intervalos ordenados)
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Binary search operations (on sorted ranges)
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Definir operações (em intervalos ordenados)
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Set operations (on sorted ranges)
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set_difference
set_intersection
set_symmetric_difference
set_union
Operações de pilha
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Heap operations
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Mínimo / máximo de operações
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Minimum/maximum operations
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Operações numéricas
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Numeric operations
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C biblioteca
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C library
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Defined in header <algorithm>
template< class InputIt1, class InputIt2, class OutputIt >

OutputIt set_symmetric_difference( InputIt1 first1, InputIt1 last1,
                                   InputIt2 first2, InputIt2 last2,

                                   OutputIt d_first );
(1)
template< class InputIt1, class InputIt2,

          class OutputIt, class Compare >
OutputIt set_symmetric_difference( InputIt1 first1, InputIt1 last1,
                                   InputIt2 first2, InputIt2 last2,

                                   OutputIt d_first, Compare comp );
(2)
Copia os elementos da gama [first1, last1) ordenada, que não se encontram na gama [first2, last2) ordenadas e os elementos da gama [first2, last2) ordenada, que não se encontram na gama [first1, last1) ordenadas para o início de intervalo d_first. O intervalo resultante é também classificada. A primeira versão espera que tanto a entrada varia de ser resolvido com operator<, a segunda versão espera que sejam classificados com o comp dada função de comparação. Se algum elemento é encontrado m vezes em [first1, last1) e n vezes em [first2, last2), ele será copiado para d_first exactamente std::abs(m-n) vezes. Se m>n, então o m-n último desses elementos são copiados do [first1,last1), caso contrário os elementos n-m últimos são copiados de [first2,last2). O intervalo resultante não pode sobrepor-se a qualquer das faixas de entrada.
Original:
Copies the elements from the sorted range [first1, last1) which are not found in the sorted range [first2, last2) and the elements from the sorted range [first2, last2) which are not found in the sorted range [first1, last1) to the range beginning at d_first. The resulting range is also sorted. The first version expects both input ranges to be sorted with operator<, the second version expects them to be sorted with the given comparison function comp. If some element is found m times in [first1, last1) and n times in [first2, last2), it will be copied to d_first exactly std::abs(m-n) times. If m>n, then the last m-n of those elements are copied from [first1,last1), otherwise the last n-m elements are copied from [first2,last2). The resulting range cannot overlap with either of the input ranges.
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Índice

[editar] Parâmetros

first1, last1 -
o primeiro intervalo ordenada de elementos
Original:
the first sorted range of elements
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first2, last2 -
o segundo conjunto ordenado de elementos
Original:
the second sorted range of elements
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comp - comparison function which returns ​true if the first argument is less than the second.

The signature of the comparison function should be equivalent to the following:

 bool cmp(const Type1 &a, const Type2 &b);

The signature does not need to have const &, but the function must not modify the objects passed to it.
The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to Type1 and Type2 respectively. ​

Type requirements
-
InputIt1 must meet the requirements of InputIterator.
-
InputIt2 must meet the requirements of InputIterator.
-
OutputIt must meet the requirements of OutputIterator.

[editar] Valor de retorno

Iterator após o final do intervalo construída.
Original:
Iterator past the end of the constructed range.
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[editar] Complexidade

Na maioria das comparações dos 2·(N1+N2-1), onde N1 = std::distance(first1, last1) e N2 = std::distance(first2, last2).
Original:
At most 2·(N1+N2-1) comparisons, where N1 = std::distance(first1, last1) and N2 = std::distance(first2, last2).
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[editar] Possível implementação

First version
template<class InputIt1, class InputIt2, class OutputIt>
OutputIt set_difference(InputIt1 first1, InputIt1 last1,
                        InputIt2 first2, InputIt2 last2,
                        OutputIt d_first)
{
    while (first1 != last1) {
        if (first2 == last2) return std::copy(first1, last1, d_first);
 
        if (*first1 < *first2) {
            *d_first++ = *first1++;
        } else {
            if (*first2 < *first1) {
                *d_first++ = *first2;
            } else {
                ++first1;
            }
            ++first2;
        }
    }
    return std::copy(first2, last2, d_first);
}
Second version
template<class InputIt1, class InputIt2,
         class OutputIt, class Compare>
OutputIt set_difference(InputIt1 first1, InputIt1 last1,
                        InputIt2 first2, InputIt2 last2,
                        OutputIt d_first, Compare comp)
{
    while (first1 != last1) {
        if (first2 == last2) return std::copy(first1, last1, d_first);
 
        if (comp(*first1, *first2)) {
            *d_first++ = *first1++;
        } else {
            if (comp(*first2, *first1)) {
                *d_first++ = *first2;
            } else {
                ++first1;
            }
            ++first2;
        }
    }
    return std::copy(first2, last2, d_first);
}

[editar] Exemplo

#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>
int main()
{
    std::vector<int> v1{1,2,3,4,5,6,7,8     };
    std::vector<int> v2{        5,  7,  9,10};
    std::sort(v1.begin(), v1.end());
    std::sort(v2.begin(), v2.end());
 
    std::vector<int> v_intersection;
 
    std::set_symmetric_difference(
        v1.begin(), v1.end(),
        v2.begin(), v2.end(),
        std::back_inserter(v_intersection));
 
    for(int n : v_intersection)
        std::cout << n << ' ';
}

Output:

1 2 3 4 6 8 9 10

[editar] Veja também

devolve verdadeiro se um conjunto é um subconjunto de uma outra
Original:
returns true if one set is a subset of another
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(modelo de função) [edit]
calcula a diferença entre os dois conjuntos
Original:
computes the difference between two sets
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(modelo de função) [edit]
computes the union of two sets
(modelo de função) [edit]
calcula a interseção de dois conjuntos
Original:
computes the intersection of two sets
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(modelo de função) [edit]